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2. Polynomials
easy
Find the zero of the polynomial : $p(x)=c x+d, \,c \neq 0, \,c,\,d$ are real numbers.
A
$-\frac{ d }{ c }$
B
$d$
C
$\frac{ d }{ c }$
D
$-\frac{ c }{ d }$
Solution
Since $p ( x )= cx + d$ $\therefore $ $p ( x )=0$
$\Rightarrow$ $c x+d=0$ or $c x=-\,d$
or $x=-\,\frac{d}{c}$
Thus, a zero of $cx + d$ is $-\frac{ d }{ c }$
Standard 9
Mathematics
